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10th Grade Arithmetic and Geometric Sequences Worksheet — Level 3 — Practice Set 2 — Answers

Answer sheet with worked solutions for the 10th Grade sequences & series worksheet.

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10th Grade Arithmetic and Geometric Sequences Worksheet — Level 3 — Practice Set 2 — Answers

Arithmetic: Tₙ = a + (n − 1)d. Geometric: Tₙ = arn − 1. Show your work.

1.Find the sum of the first 10 terms of the arithmetic sequence 5, 9, 13, 17, …

Answer: 230

  1. Sₙ = n/2 × (2a + (n − 1)d)
  2. = 10/2 × (2 × 5 + 9 × 4)
  3. = 230
2.For the arithmetic sequence 20, 25, 30, 35, …, write the common difference and the rule for the nth term.

Answer: d = 5; Tₙ = 5n + 15

  1. d = 25 − 20 = 5
  2. Tₙ = a + (n − 1)d = 20 + (n − 1) × 5 = 5n + 15
3.For the arithmetic sequence 6, 11, 16, 21, …, write the common difference and the rule for the nth term.

Answer: d = 5; Tₙ = 5n + 1

  1. d = 11 − 6 = 5
  2. Tₙ = a + (n − 1)d = 6 + (n − 1) × 5 = 5n + 1
4.Find the 24th term of the arithmetic sequence 16, 25, 34, 43, …

Answer: 223

  1. a = 16, d = 9
  2. T24 = 16 + 23 × 9 = 223
5.For the arithmetic sequence 0, −5, −10, −15, …, write the common difference and the rule for the nth term.

Answer: d = −5; Tₙ = −5n + 5

  1. d = −5 − 0 = −5
  2. Tₙ = a + (n − 1)d = 0 + (n − 1) × −5 = −5n + 5
6.For the arithmetic sequence 16, 12, 8, 4, …, write the common difference and the rule for the nth term.

Answer: d = −4; Tₙ = −4n + 20

  1. d = 12 − 16 = −4
  2. Tₙ = a + (n − 1)d = 16 + (n − 1) × −4 = −4n + 20
7.Find the sum of the first 6 terms of the geometric sequence 5, 15, 45, 135, …

Answer: 1820

  1. Sₙ = a(rⁿ − 1) ÷ (r − 1)
  2. = 5 × (36 − 1) ÷ (3 − 1)
  3. = 1820
8.For the geometric sequence 5, 20, 80, 320, …, write the common ratio and the rule for the nth term.

Answer: r = 4; Tₙ = 5 × 4n − 1

  1. r = 20 ÷ 5 = 4
9.Find the sum of the first 9 terms of the geometric sequence 8, 40, 200, 1000, …

Answer: 3906248

  1. Sₙ = a(rⁿ − 1) ÷ (r − 1)
  2. = 8 × (59 − 1) ÷ (5 − 1)
  3. = 3906248
10.Find the sum of the first 23 terms of the arithmetic sequence −5, −7, −9, −11, …

Answer: −621

  1. Sₙ = n/2 × (2a + (n − 1)d)
  2. = 23/2 × (2 × −5 + 22 × −2)
  3. = −621
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