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10th Grade Systems of Equations Worksheet — Level 3 — Practice Set 2 — Answers

Answer sheet with worked solutions for the 10th Grade systems of equations worksheet.

Success TutoringWorksheetsAnswer sheet10th Grade · Mathematics · Simultaneous Equations

10th Grade Systems of Equations Worksheet — Level 3 — Practice Set 2 — Answers

Solve each pair of equations. Check your solution satisfies both equations.

1.Solve the system: 3x − y = 2 and 5x − 4y = −6

Answer: x = 2, y = 4

  1. Multiply equation 1 by 5 and equation 2 by 3 to match the x coefficients
  2. 15x − 5y = 10 and 15x − 12y = −18
  3. Subtract: 7y = 28, so y = 4
  4. Substitute back: x = 2
2.Solve the system: 3x + 2y = −5 and 3x + 3y = −3

Answer: x = −3, y = 2

  1. Subtract equation 2 from equation 1: −y = −2
  2. y = 2
  3. Substitute into equation 1: 3x + 4 = −5, so x = −3
3.Solve the system: 3x − 3y = 9 and 4x − 5y = 18

Answer: x = −3, y = −6

  1. Multiply equation 1 by 4 and equation 2 by 3 to match the x coefficients
  2. 12x − 12y = 36 and 12x − 15y = 54
  3. Subtract: 3y = −18, so y = −6
  4. Substitute back: x = −3
4.Solve the system: 4x − 4y = −12 and 2x + 5y = 50

Answer: x = 5, y = 8

  1. Multiply equation 1 by 2 and equation 2 by 4 to match the x coefficients
  2. 8x − 8y = −24 and 8x + 20y = 200
  3. Subtract: −28y = −224, so y = 8
  4. Substitute back: x = 5
5.Solve the system: 2x + 2y = 2 and 4x + y = 16

Answer: x = 5, y = −4

  1. Multiply equation 1 by 4 and equation 2 by 2 to match the x coefficients
  2. 8x + 8y = 8 and 8x + 2y = 32
  3. Subtract: 6y = −24, so y = −4
  4. Substitute back: x = 5
6.Solve the system: 2x + 3y = 0 and 2x + y = −8

Answer: x = −6, y = 4

  1. Subtract equation 2 from equation 1: 2y = 8
  2. y = 4
  3. Substitute into equation 1: 2x + 12 = 0, so x = −6
7.Solve the system: 2x − y = 12 and 3x − 4y = 28

Answer: x = 4, y = −4

  1. Multiply equation 1 by 3 and equation 2 by 2 to match the x coefficients
  2. 6x − 3y = 36 and 6x − 8y = 56
  3. Subtract: 5y = −20, so y = −4
  4. Substitute back: x = 4
8.Solve the system: 2x + 4y = 8 and 4x + 5y = 19

Answer: x = 6, y = −1

  1. Multiply equation 1 by 4 and equation 2 by 2 to match the x coefficients
  2. 8x + 16y = 32 and 8x + 10y = 38
  3. Subtract: 6y = −6, so y = −1
  4. Substitute back: x = 6
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