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10th Grade Trigonometry (Finding Sides) Worksheet — Level 2 — Practice Set 4 — Answers

Answer sheet with worked solutions for the 10th Grade trigonometry worksheet.

Success TutoringWorksheetsAnswer sheet10th Grade · Mathematics · Trigonometry

10th Grade Trigonometry (Finding Sides) Worksheet — Level 2 — Practice Set 4 — Answers

Label the sides (opposite, adjacent, hypotenuse), choose the ratio (SOH CAH TOA), then solve.

1.In a right triangle, the hypotenuse is 26 cm and one angle is 56°. Find the side adjacent to the 56° angle, to 1 decimal place.

Answer: 14.5 cm

  1. cos 56° = adjacent ÷ hypotenuse
  2. adjacent = 26 × cos 56°
  3. ≈ 14.5
2.In a right triangle, the hypotenuse is 22 cm and one angle is 62°. Find the side opposite the 62° angle, to 1 decimal place.

Answer: 19.4 cm

  1. sin 62° = opposite ÷ hypotenuse
  2. opposite = 22 × sin 62°
  3. ≈ 19.4
3.In a right triangle, the side adjacent to a 68° angle is 14 m. Find the opposite side, to 1 decimal place.

Answer: 34.7 m

  1. tan 68° = opposite ÷ adjacent
  2. opposite = 14 × tan 68°
  3. ≈ 34.7
4.In a right triangle, the hypotenuse is 13 cm and one angle is 60°. Find the side adjacent to the 60° angle, to 1 decimal place.

Answer: 6.5 cm

  1. cos 60° = adjacent ÷ hypotenuse
  2. adjacent = 13 × cos 60°
  3. ≈ 6.5
5.In a right triangle, the hypotenuse is 16 cm and one angle is 35°. Find the side opposite the 35° angle, to 1 decimal place.

Answer: 9.2 cm

  1. sin 35° = opposite ÷ hypotenuse
  2. opposite = 16 × sin 35°
  3. ≈ 9.2
6.In a right triangle, the side adjacent to a 61° angle is 12 m. Find the opposite side, to 1 decimal place.

Answer: 21.6 m

  1. tan 61° = opposite ÷ adjacent
  2. opposite = 12 × tan 61°
  3. ≈ 21.6
7.In a right triangle, the side adjacent to a 70° angle is 15 m. Find the opposite side, to 1 decimal place.

Answer: 41.2 m

  1. tan 70° = opposite ÷ adjacent
  2. opposite = 15 × tan 70°
  3. ≈ 41.2
8.In a right triangle, the side adjacent to a 22° angle is 22 m. Find the opposite side, to 1 decimal place.

Answer: 8.9 m

  1. tan 22° = opposite ÷ adjacent
  2. opposite = 22 × tan 22°
  3. ≈ 8.9
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