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Rates of Reaction and Collision Theory — Answers

Answer sheet with model answers and success criteria for the 10th Grade mixtures & chemical reactions worksheet.

Success TutoringWorksheetsAnswer sheet10th Grade · Science · Mixtures & Chemical Reactions

Rates of Reaction and Collision Theory — Answers

Part A: Collision theory

Collision theory: particles can react only when they collide with enough energy (the activation energy) and in the right orientation. Anything that makes successful collisions happen more often increases the rate of reaction.

The rate increases with higher temperature, higher concentration (or pressure for gases), greater surface area (smaller pieces) and the use of a catalyst.

1.State the two conditions needed for a collision between particles to result in a reaction.

Answer: The particles must collide with enough energy (at least the activation energy) and in the correct orientation.

2.Why does increasing the temperature increase the rate of a reaction?
  1. AParticles become larger
  2. BParticles move faster, collide more often and more collisions have enough energy to react
  3. CThe activation energy increases
  4. DMore product is made in total

Answer: Particles move faster, collide more often and more collisions have enough energy to react

Both the frequency of collisions and the proportion of successful collisions increase.

3.Explain, using collision theory, why powdered marble reacts faster with acid than the same mass of marble chips.

Answer: The powder has a much larger surface area, so more particles are exposed to the acid. This gives more frequent collisions between acid particles and marble particles, so the rate is higher.

4.Explain why increasing the concentration of an acid increases the rate of reaction with magnesium.

Answer: A more concentrated acid has more acid particles in the same volume, so they collide with the magnesium surface more often, giving more successful collisions per second.

5.What is a catalyst, and how does it speed up a reaction?

Answer: A substance that speeds up a reaction without being used up. It provides an alternative pathway with a lower activation energy, so a greater proportion of collisions are successful.

6.A catalyst increases the total amount of product made in a reaction.

Answer: False

A catalyst only makes the reaction reach the end faster. The amount of product depends on the amount of reactants.

Part B: Measuring rate

Marble chips (calcium carbonate, in excess) react with hydrochloric acid, producing carbon dioxide gas, which is collected in a gas syringe.

Volume of gas (cm³) — 0 s: 0 · 10 s: 24 · 20 s: 40 · 30 s: 50 · 40 s: 55 · 50 s: 56 · 60 s: 56

Average rate = amount of product formed ÷ time taken.

7.Balance: CaCO₃ + HCl → CaCl₂ + H₂O + CO₂

Answer: CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂

  1. Left: Ca 1, C 1, O 3, H 2, Cl 2
  2. Right: Ca 1, Cl 2, H 2, O 1 + 2 = 3, C 1 (balanced)
8.Calculate the average rate of reaction over the first 20 seconds.

Answer: 2.0 cm³/s

  1. rate = volume of gas ÷ time
  2. 40 ÷ 20 = 2.0 cm³/s
9.Calculate the average rate between 20 s and 40 s.

Answer: 0.75 cm³/s

  1. Gas produced = 55 − 40 = 15 cm³
  2. 15 ÷ 20 = 0.75 cm³/s
10.The reaction finished at 50 s. Calculate the average rate for the whole reaction.

Answer: 1.12 cm³/s

  1. 56 ÷ 50 = 1.12 cm³/s
11.Explain why the reaction slows down and then stops.

Answer: As the reaction goes on, the reactants are used up, so their particles become less concentrated and collide less often. The rate falls, and the reaction stops when one reactant (here the acid, since chips were in excess) is used up.

12.The experiment is repeated with acid at the same volume but double the concentration, with marble chips still in excess. Describe how the results would differ.

Answer: The gas would be produced faster at the start (a steeper graph), and the reaction would finish sooner. Because there is twice as much acid, about twice as much gas (about 112 cm³) would be produced in total.

Part C: Temperature and catalysts

13.A reaction takes 80 s to finish at 20 °C. Using the rule of thumb that a 10 °C rise roughly doubles the rate, estimate how long it would take at 40 °C.

Answer: About 20 s

  1. 20 °C → 30 °C: rate doubles, time halves to 40 s
  2. 30 °C → 40 °C: time halves again to 20 s
14.Rate can be estimated as 1 ÷ time. Calculate the rate for a reaction that takes 40 s.

Answer: 0.025 s⁻¹

  1. 1 ÷ 40 = 0.025 s⁻¹
15.Hydrogen peroxide breaks down slowly into water and oxygen. Adding a little manganese dioxide makes it fizz rapidly, and the manganese dioxide can be recovered afterwards. Write the balanced equation and explain what the manganese dioxide is doing.

Answer: 2H₂O₂ → 2H₂O + O₂. The manganese dioxide is a catalyst: it speeds up the reaction without being used up, which is why the same mass can be recovered at the end.

Part D: Design an investigation

16.Plan an investigation to find out how the temperature of hydrochloric acid affects how quickly a 2 cm piece of magnesium ribbon reacts. Include the variables, a method, safety precautions and how you would present your results.[4 marks]

Model answer: Independent variable: temperature of the acid (for example 20, 30, 40, 50 °C). Dependent variable: time for the magnesium to disappear completely (or volume of hydrogen collected in 30 s). Controlled variables: the volume and concentration of acid, the length (mass) of magnesium ribbon, the type of container and whether it is stirred. Method: warm 25 mL of acid in a water bath to each temperature, checking with a thermometer; add a 2 cm piece of magnesium and start the stopwatch; stop it when the magnesium has disappeared. Repeat three times at each temperature and calculate the mean, ignoring outliers. Safety: wear safety glasses, use dilute acid, avoid naked flames because hydrogen is flammable, and use a water bath to heat the acid. Results: record in a table and draw a line graph of temperature (x-axis) against mean time (or rate = 1 ÷ time) on the y-axis.

Success criteria:

  • Correct independent, dependent and controlled variables
  • Clear, repeatable method including repeats and means
  • At least two relevant safety precautions
  • Appropriate table and graph described
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