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11th Grade Trigonometry (Finding Sides) Worksheet — Level 3 — Answers

Answer sheet with worked solutions for the 11th Grade trigonometry worksheet.

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Success TutoringWorksheetsAnswer sheet11th Grade · Mathematics · Trigonometry

11th Grade Trigonometry (Finding Sides) Worksheet — Level 3 — Answers

Label the sides (opposite, adjacent, hypotenuse), choose the ratio (SOH CAH TOA), then solve.

1.In a right triangle, the hypotenuse is 7 cm and one angle is 66°. Find the side adjacent to the 66° angle, to 1 decimal place.

Answer: 2.8 cm

  1. cos 66° = adjacent ÷ hypotenuse
  2. adjacent = 7 × cos 66°
  3. ≈ 2.8
2.In a right triangle, the side adjacent to a 52° angle is 8 m. Find the opposite side, to 1 decimal place.

Answer: 10.2 m

  1. tan 52° = opposite ÷ adjacent
  2. opposite = 8 × tan 52°
  3. ≈ 10.2
3.In a right triangle, the hypotenuse is 14 cm and one angle is 43°. Find the side opposite the 43° angle, to 1 decimal place.

Answer: 9.5 cm

  1. sin 43° = opposite ÷ hypotenuse
  2. opposite = 14 × sin 43°
  3. ≈ 9.5
4.In a right triangle, the side adjacent to a 22° angle is 12 m. Find the opposite side, to 1 decimal place.

Answer: 4.8 m

  1. tan 22° = opposite ÷ adjacent
  2. opposite = 12 × tan 22°
  3. ≈ 4.8
5.In a right triangle, the hypotenuse is 26 cm and one angle is 65°. Find the side adjacent to the 65° angle, to 1 decimal place.

Answer: 11 cm

  1. cos 65° = adjacent ÷ hypotenuse
  2. adjacent = 26 × cos 65°
  3. ≈ 11
6.In a right triangle, the side adjacent to a 31° angle is 6 m. Find the opposite side, to 1 decimal place.

Answer: 3.6 m

  1. tan 31° = opposite ÷ adjacent
  2. opposite = 6 × tan 31°
  3. ≈ 3.6
7.In a right triangle, the side adjacent to a 62° angle is 10 m. Find the opposite side, to 1 decimal place.

Answer: 18.8 m

  1. tan 62° = opposite ÷ adjacent
  2. opposite = 10 × tan 62°
  3. ≈ 18.8
8.In a right triangle, the hypotenuse is 15 cm and one angle is 27°. Find the side opposite the 27° angle, to 1 decimal place.

Answer: 6.8 cm

  1. sin 27° = opposite ÷ hypotenuse
  2. opposite = 15 × sin 27°
  3. ≈ 6.8
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