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11th Grade Trigonometry (Finding Sides) Worksheet — Level 3 — Practice Set 2 — Answers

Answer sheet with worked solutions for the 11th Grade trigonometry worksheet.

Success TutoringWorksheetsAnswer sheet11th Grade · Mathematics · Trigonometry

11th Grade Trigonometry (Finding Sides) Worksheet — Level 3 — Practice Set 2 — Answers

Label the sides (opposite, adjacent, hypotenuse), choose the ratio (SOH CAH TOA), then solve.

1.In a right triangle, the side adjacent to a 45° angle is 4 m. Find the opposite side, to 1 decimal place.

Answer: 4 m

  1. tan 45° = opposite ÷ adjacent
  2. opposite = 4 × tan 45°
  3. ≈ 4
2.In a right triangle, the hypotenuse is 12 cm and one angle is 47°. Find the side opposite the 47° angle, to 1 decimal place.

Answer: 8.8 cm

  1. sin 47° = opposite ÷ hypotenuse
  2. opposite = 12 × sin 47°
  3. ≈ 8.8
3.In a right triangle, the hypotenuse is 18 cm and one angle is 33°. Find the side opposite the 33° angle, to 1 decimal place.

Answer: 9.8 cm

  1. sin 33° = opposite ÷ hypotenuse
  2. opposite = 18 × sin 33°
  3. ≈ 9.8
4.In a right triangle, the hypotenuse is 6 cm and one angle is 39°. Find the side adjacent to the 39° angle, to 1 decimal place.

Answer: 4.7 cm

  1. cos 39° = adjacent ÷ hypotenuse
  2. adjacent = 6 × cos 39°
  3. ≈ 4.7
5.In a right triangle, the side adjacent to a 30° angle is 22 m. Find the opposite side, to 1 decimal place.

Answer: 12.7 m

  1. tan 30° = opposite ÷ adjacent
  2. opposite = 22 × tan 30°
  3. ≈ 12.7
6.In a right triangle, the hypotenuse is 7 cm and one angle is 47°. Find the side opposite the 47° angle, to 1 decimal place.

Answer: 5.1 cm

  1. sin 47° = opposite ÷ hypotenuse
  2. opposite = 7 × sin 47°
  3. ≈ 5.1
7.In a right triangle, the hypotenuse is 12 cm and one angle is 54°. Find the side opposite the 54° angle, to 1 decimal place.

Answer: 9.7 cm

  1. sin 54° = opposite ÷ hypotenuse
  2. opposite = 12 × sin 54°
  3. ≈ 9.7
8.In a right triangle, the side adjacent to a 51° angle is 8 m. Find the opposite side, to 1 decimal place.

Answer: 9.9 m

  1. tan 51° = opposite ÷ adjacent
  2. opposite = 8 × tan 51°
  3. ≈ 9.9
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