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11th Grade Trigonometry (Finding Sides) Worksheet — Level 2 — Answers

Answer sheet with worked solutions for the 11th Grade trigonometry worksheet.

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Success TutoringWorksheetsAnswer sheet11th Grade · Mathematics · Trigonometry

11th Grade Trigonometry (Finding Sides) Worksheet — Level 2 — Answers

Label the sides (opposite, adjacent, hypotenuse), choose the ratio (SOH CAH TOA), then solve.

1.In a right triangle, the hypotenuse is 21 cm and one angle is 55°. Find the side opposite the 55° angle, to 1 decimal place.

Answer: 17.2 cm

  1. sin 55° = opposite ÷ hypotenuse
  2. opposite = 21 × sin 55°
  3. ≈ 17.2
2.In a right triangle, the hypotenuse is 19 cm and one angle is 46°. Find the side opposite the 46° angle, to 1 decimal place.

Answer: 13.7 cm

  1. sin 46° = opposite ÷ hypotenuse
  2. opposite = 19 × sin 46°
  3. ≈ 13.7
3.In a right triangle, the hypotenuse is 6 cm and one angle is 43°. Find the side opposite the 43° angle, to 1 decimal place.

Answer: 4.1 cm

  1. sin 43° = opposite ÷ hypotenuse
  2. opposite = 6 × sin 43°
  3. ≈ 4.1
4.In a right triangle, the hypotenuse is 8 cm and one angle is 42°. Find the side opposite the 42° angle, to 1 decimal place.

Answer: 5.4 cm

  1. sin 42° = opposite ÷ hypotenuse
  2. opposite = 8 × sin 42°
  3. ≈ 5.4
5.In a right triangle, the side adjacent to a 29° angle is 10 m. Find the opposite side, to 1 decimal place.

Answer: 5.5 m

  1. tan 29° = opposite ÷ adjacent
  2. opposite = 10 × tan 29°
  3. ≈ 5.5
6.In a right triangle, the hypotenuse is 7 cm and one angle is 65°. Find the side adjacent to the 65° angle, to 1 decimal place.

Answer: 3 cm

  1. cos 65° = adjacent ÷ hypotenuse
  2. adjacent = 7 × cos 65°
  3. ≈ 3
7.In a right triangle, the side adjacent to a 38° angle is 8 m. Find the opposite side, to 1 decimal place.

Answer: 6.3 m

  1. tan 38° = opposite ÷ adjacent
  2. opposite = 8 × tan 38°
  3. ≈ 6.3
8.In a right triangle, the side adjacent to a 63° angle is 14 m. Find the opposite side, to 1 decimal place.

Answer: 27.5 m

  1. tan 63° = opposite ÷ adjacent
  2. opposite = 14 × tan 63°
  3. ≈ 27.5
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