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11th Grade Trigonometry (Finding Sides) Worksheet — Level 2 — Practice Set 4 — Answers

Answer sheet with worked solutions for the 11th Grade trigonometry worksheet.

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11th Grade Trigonometry (Finding Sides) Worksheet — Level 2 — Practice Set 4 — Answers

Label the sides (opposite, adjacent, hypotenuse), choose the ratio (SOH CAH TOA), then solve.

1.In a right triangle, the side adjacent to a 43° angle is 16 m. Find the opposite side, to 1 decimal place.

Answer: 14.9 m

  1. tan 43° = opposite ÷ adjacent
  2. opposite = 16 × tan 43°
  3. ≈ 14.9
2.In a right triangle, the hypotenuse is 8 cm and one angle is 48°. Find the side opposite the 48° angle, to 1 decimal place.

Answer: 5.9 cm

  1. sin 48° = opposite ÷ hypotenuse
  2. opposite = 8 × sin 48°
  3. ≈ 5.9
3.In a right triangle, the hypotenuse is 13 cm and one angle is 57°. Find the side opposite the 57° angle, to 1 decimal place.

Answer: 10.9 cm

  1. sin 57° = opposite ÷ hypotenuse
  2. opposite = 13 × sin 57°
  3. ≈ 10.9
4.In a right triangle, the hypotenuse is 11 cm and one angle is 64°. Find the side adjacent to the 64° angle, to 1 decimal place.

Answer: 4.8 cm

  1. cos 64° = adjacent ÷ hypotenuse
  2. adjacent = 11 × cos 64°
  3. ≈ 4.8
5.In a right triangle, the hypotenuse is 30 cm and one angle is 65°. Find the side opposite the 65° angle, to 1 decimal place.

Answer: 27.2 cm

  1. sin 65° = opposite ÷ hypotenuse
  2. opposite = 30 × sin 65°
  3. ≈ 27.2
6.In a right triangle, the hypotenuse is 15 cm and one angle is 60°. Find the side opposite the 60° angle, to 1 decimal place.

Answer: 13 cm

  1. sin 60° = opposite ÷ hypotenuse
  2. opposite = 15 × sin 60°
  3. ≈ 13
7.In a right triangle, the side adjacent to a 39° angle is 10 m. Find the opposite side, to 1 decimal place.

Answer: 8.1 m

  1. tan 39° = opposite ÷ adjacent
  2. opposite = 10 × tan 39°
  3. ≈ 8.1
8.In a right triangle, the hypotenuse is 23 cm and one angle is 50°. Find the side adjacent to the 50° angle, to 1 decimal place.

Answer: 14.8 cm

  1. cos 50° = adjacent ÷ hypotenuse
  2. adjacent = 23 × cos 50°
  3. ≈ 14.8
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