6th Grade Circumference and Area of Circles Worksheet — Level 3 — Answers
Answer sheet with worked solutions for the 6th Grade area & perimeter worksheet.
6th Grade Circumference and Area of Circles Worksheet — Level 3 — Answers
Show your work. Use the π button on your calculator and round to 1 decimal place unless told otherwise.
1.A circle has a diameter of 30 cm. Find its area, correct to 1 decimal place.
Answer: 706.9 cm2
- r = 30 ÷ 2 = 15 cm
- A = π × r2 = π × 152 = π × 225
- ≈ 706.9 cm2
2.A circle has a circumference of 28π cm. Find its radius and its area (leave the area in terms of π).
Answer: r = 14 cm; A = 196π cm2
- C = 2πr, so 2πr = 28π
- r = 14 cm
- A = πr2 = 196π cm2
3.A circle has a diameter of 34 cm. Find its area, correct to 1 decimal place.
Answer: 907.9 cm2
- r = 34 ÷ 2 = 17 cm
- A = π × r2 = π × 172 = π × 289
- ≈ 907.9 cm2
4.A circle has a circumference of 10π cm. Find its radius and its area (leave the area in terms of π).
Answer: r = 5 cm; A = 25π cm2
- C = 2πr, so 2πr = 10π
- r = 5 cm
- A = πr2 = 25π cm2
5.A circle has a diameter of 4 cm. Find its area, correct to 1 decimal place.
Answer: 12.6 cm2
- r = 4 ÷ 2 = 2 cm
- A = π × r2 = π × 22 = π × 4
- ≈ 12.6 cm2
6.A circle has a circumference of 26π cm. Find its radius and its area (leave the area in terms of π).
Answer: r = 13 cm; A = 169π cm2
- C = 2πr, so 2πr = 26π
- r = 13 cm
- A = πr2 = 169π cm2
7.A circle has a circumference of 14π cm. Find its radius and its area (leave the area in terms of π).
Answer: r = 7 cm; A = 49π cm2
- C = 2πr, so 2πr = 14π
- r = 7 cm
- A = πr2 = 49π cm2
8.A circle has a circumference of 8π cm. Find its radius and its area (leave the area in terms of π).
Answer: r = 4 cm; A = 16π cm2
- C = 2πr, so 2πr = 8π
- r = 4 cm
- A = πr2 = 16π cm2
9.A circle has a circumference of 4π cm. Find its radius and its area (leave the area in terms of π).
Answer: r = 2 cm; A = 4π cm2
- C = 2πr, so 2πr = 4π
- r = 2 cm
- A = πr2 = 4π cm2
10.A circle has a radius of 17 cm. Find its area, correct to 1 decimal place.
Answer: 907.9 cm2
- A = π × r2 = π × 172 = π × 289
- ≈ 907.9 cm2
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