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6th Grade Circumference and Area of Circles Worksheet — Level 3 — Practice Set 2 — Answers

Answer sheet with worked solutions for the 6th Grade area & perimeter worksheet.

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Success TutoringWorksheetsAnswer sheet6th Grade · Mathematics · Area & Perimeter

6th Grade Circumference and Area of Circles Worksheet — Level 3 — Practice Set 2 — Answers

Show your work. Use the π button on your calculator and round to 1 decimal place unless told otherwise.

1.A circle has a circumference of 38π cm. Find its radius and its area (leave the area in terms of π).

Answer: r = 19 cm; A = 361π cm2

  1. C = 2πr, so 2πr = 38π
  2. r = 19 cm
  3. A = πr2 = 361π cm2
2.A circle has a diameter of 20 cm. Find its area, correct to 1 decimal place.

Answer: 314.2 cm2

  1. r = 20 ÷ 2 = 10 cm
  2. A = π × r2 = π × 102 = π × 100
  3. ≈ 314.2 cm2
3.Find the area of a semicircle with a radius of 11 cm, correct to 1 decimal place.

Answer: 190.1 cm2

  1. A = ½ × π × r2 = ½ × π × 121
  2. ≈ 190.1 cm2
4.Find the area of a semicircle with a radius of 7 cm, correct to 1 decimal place.

Answer: 77.0 cm2

  1. A = ½ × π × r2 = ½ × π × 49
  2. ≈ 77.0 cm2
5.A circle has a circumference of 14π cm. Find its radius and its area (leave the area in terms of π).

Answer: r = 7 cm; A = 49π cm2

  1. C = 2πr, so 2πr = 14π
  2. r = 7 cm
  3. A = πr2 = 49π cm2
6.A circle has a diameter of 12 cm. Find its area, correct to 1 decimal place.

Answer: 113.1 cm2

  1. r = 12 ÷ 2 = 6 cm
  2. A = π × r2 = π × 62 = π × 36
  3. ≈ 113.1 cm2
7.A circle has a radius of 18 cm. Find its area, correct to 1 decimal place.

Answer: 1017.9 cm2

  1. A = π × r2 = π × 182 = π × 324
  2. ≈ 1017.9 cm2
8.Find the area of a semicircle with a radius of 20 cm, correct to 1 decimal place.

Answer: 628.3 cm2

  1. A = ½ × π × r2 = ½ × π × 400
  2. ≈ 628.3 cm2
9.A circle has a circumference of 12π cm. Find its radius and its area (leave the area in terms of π).

Answer: r = 6 cm; A = 36π cm2

  1. C = 2πr, so 2πr = 12π
  2. r = 6 cm
  3. A = πr2 = 36π cm2
10.A circle has a circumference of 4π cm. Find its radius and its area (leave the area in terms of π).

Answer: r = 2 cm; A = 4π cm2

  1. C = 2πr, so 2πr = 4π
  2. r = 2 cm
  3. A = πr2 = 4π cm2
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