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6th Grade Coordinates: Quadrants, Midpoints and Distance Worksheet — Level 3 — Practice Set 2 — Answers

Answer sheet with worked solutions for the 6th Grade geometry worksheet.

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Success TutoringWorksheetsAnswer sheet6th Grade · Mathematics · Geometry

6th Grade Coordinates: Quadrants, Midpoints and Distance Worksheet — Level 3 — Practice Set 2 — Answers

Midpoint = (average of the x-values, average of the y-values). Distance: use Pythagoras with the horizontal and vertical changes.

1.Find the midpoint of the segment joining (0, −4) and (9, 0).

Answer: (4.5, −2)

  1. x: (0 + 9) ÷ 2 = 4.5
  2. y: (−4 + 0) ÷ 2 = −2
2.Find the midpoint of the segment joining (6, 6) and (8, 5).

Answer: (7, 5.5)

  1. x: (6 + 8) ÷ 2 = 7
  2. y: (6 + 5) ÷ 2 = 5.5
3.Find the midpoint of the segment joining (4, 9) and (9, −9).

Answer: (6.5, 0)

  1. x: (4 + 9) ÷ 2 = 6.5
  2. y: (9 + (−9)) ÷ 2 = 0
4.Find the midpoint of the segment joining (7, 3) and (−2, 8).

Answer: (2.5, 5.5)

  1. x: (7 + (−2)) ÷ 2 = 2.5
  2. y: (3 + 8) ÷ 2 = 5.5
5.Find the distance between (5, −2) and (13, −17).

Answer: 17

  1. Horizontal change = 8, vertical change = 15
  2. d = √(82 + 152) = √289
  3. = 17
6.Find the midpoint of the segment joining (3, 6) and (−3, 4).

Answer: (0, 5)

  1. x: (3 + (−3)) ÷ 2 = 0
  2. y: (6 + 4) ÷ 2 = 5
7.Find the midpoint of the segment joining (4, −5) and (6, 3).

Answer: (5, −1)

  1. x: (4 + 6) ÷ 2 = 5
  2. y: (−5 + 3) ÷ 2 = −1
8.Find the midpoint of the segment joining (3, 5) and (−6, −1).

Answer: (−1.5, 2)

  1. x: (3 + (−6)) ÷ 2 = −1.5
  2. y: (5 + (−1)) ÷ 2 = 2
9.Find the midpoint of the segment joining (−1, −3) and (−8, −2).

Answer: (−4.5, −2.5)

  1. x: (−1 + (−8)) ÷ 2 = −4.5
  2. y: (−3 + (−2)) ÷ 2 = −2.5
10.Find the midpoint of the segment joining (3, −3) and (−9, 4).

Answer: (−3, 0.5)

  1. x: (3 + (−9)) ÷ 2 = −3
  2. y: (−3 + 4) ÷ 2 = 0.5
11.Find the distance between (−2, −5) and (−11, 4), correct to 1 decimal place.

Answer: 12.7

  1. Horizontal change = 9, vertical change = 9
  2. d = √(92 + 92) = √162
  3. = 12.7
12.Find the distance between (2, −5) and (−4, −13).

Answer: 10

  1. Horizontal change = 6, vertical change = 8
  2. d = √(62 + 82) = √100
  3. = 10
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