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6th Grade Coordinates: Quadrants, Midpoints and Distance Worksheet — Level 3 — Practice Set 3 — Answers

Answer sheet with worked solutions for the 6th Grade geometry worksheet.

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6th Grade Coordinates: Quadrants, Midpoints and Distance Worksheet — Level 3 — Practice Set 3 — Answers

Midpoint = (average of the x-values, average of the y-values). Distance: use Pythagoras with the horizontal and vertical changes.

1.Find the midpoint of the segment joining (1, −2) and (−5, 9).

Answer: (−2, 3.5)

  1. x: (1 + (−5)) ÷ 2 = −2
  2. y: (−2 + 9) ÷ 2 = 3.5
2.Find the midpoint of the segment joining (−8, 7) and (5, −8).

Answer: (−1.5, −0.5)

  1. x: (−8 + 5) ÷ 2 = −1.5
  2. y: (7 + (−8)) ÷ 2 = −0.5
3.Find the midpoint of the segment joining (−8, 6) and (−3, 6).

Answer: (−5.5, 6)

  1. x: (−8 + (−3)) ÷ 2 = −5.5
  2. y: (6 + 6) ÷ 2 = 6
4.Find the distance between (−6, −5) and (2, −20).

Answer: 17

  1. Horizontal change = 8, vertical change = 15
  2. d = √(82 + 152) = √289
  3. = 17
5.Find the distance between (−4, 3) and (−10, 9), correct to 1 decimal place.

Answer: 8.5

  1. Horizontal change = 6, vertical change = 6
  2. d = √(62 + 62) = √72
  3. = 8.5
6.Find the midpoint of the segment joining (−7, 0) and (−4, 7).

Answer: (−5.5, 3.5)

  1. x: (−7 + (−4)) ÷ 2 = −5.5
  2. y: (0 + 7) ÷ 2 = 3.5
7.Find the distance between (0, 3) and (6, −5).

Answer: 10

  1. Horizontal change = 6, vertical change = 8
  2. d = √(62 + 82) = √100
  3. = 10
8.Find the midpoint of the segment joining (4, 4) and (7, 7).

Answer: (5.5, 5.5)

  1. x: (4 + 7) ÷ 2 = 5.5
  2. y: (4 + 7) ÷ 2 = 5.5
9.Find the midpoint of the segment joining (0, −6) and (−3, −7).

Answer: (−1.5, −6.5)

  1. x: (0 + (−3)) ÷ 2 = −1.5
  2. y: (−6 + (−7)) ÷ 2 = −6.5
10.Find the midpoint of the segment joining (−5, 0) and (−6, 3).

Answer: (−5.5, 1.5)

  1. x: (−5 + (−6)) ÷ 2 = −5.5
  2. y: (0 + 3) ÷ 2 = 1.5
11.Find the midpoint of the segment joining (−5, −9) and (−5, 2).

Answer: (−5, −3.5)

  1. x: (−5 + (−5)) ÷ 2 = −5
  2. y: (−9 + 2) ÷ 2 = −3.5
12.Find the distance between (−2, −1) and (−10, 14).

Answer: 17

  1. Horizontal change = 8, vertical change = 15
  2. d = √(82 + 152) = √289
  3. = 17
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