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7th Grade Coordinates: Quadrants, Midpoints and Distance Worksheet — Level 3 — Answers

Answer sheet with worked solutions for the 7th Grade geometry worksheet.

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Success TutoringWorksheetsAnswer sheet7th Grade · Mathematics · Geometry

7th Grade Coordinates: Quadrants, Midpoints and Distance Worksheet — Level 3 — Answers

Midpoint = (average of the x-values, average of the y-values). Distance: use Pythagoras with the horizontal and vertical changes.

1.Find the distance between (4, −6) and (7, −2).

Answer: 5

  1. Horizontal change = 3, vertical change = 4
  2. d = √(32 + 42) = √25
  3. = 5
2.Find the midpoint of the segment joining (−8, −5) and (6, 5).

Answer: (−1, 0)

  1. x: (−8 + 6) ÷ 2 = −1
  2. y: (−5 + 5) ÷ 2 = 0
3.Find the distance between (4, −1) and (6, −10), correct to 1 decimal place.

Answer: 9.2

  1. Horizontal change = 2, vertical change = 9
  2. d = √(22 + 92) = √85
  3. = 9.2
4.Find the distance between (4, 5) and (9, 4), correct to 1 decimal place.

Answer: 5.1

  1. Horizontal change = 5, vertical change = 1
  2. d = √(52 + 12) = √26
  3. = 5.1
5.Find the midpoint of the segment joining (4, 8) and (5, −4).

Answer: (4.5, 2)

  1. x: (4 + 5) ÷ 2 = 4.5
  2. y: (8 + (−4)) ÷ 2 = 2
6.Find the midpoint of the segment joining (0, −1) and (1, −4).

Answer: (0.5, −2.5)

  1. x: (0 + 1) ÷ 2 = 0.5
  2. y: (−1 + (−4)) ÷ 2 = −2.5
7.Find the distance between (−3, −6) and (6, 6).

Answer: 15

  1. Horizontal change = 9, vertical change = 12
  2. d = √(92 + 122) = √225
  3. = 15
8.Find the midpoint of the segment joining (−6, −1) and (−7, −8).

Answer: (−6.5, −4.5)

  1. x: (−6 + (−7)) ÷ 2 = −6.5
  2. y: (−1 + (−8)) ÷ 2 = −4.5
9.Find the midpoint of the segment joining (1, 4) and (3, −9).

Answer: (2, −2.5)

  1. x: (1 + 3) ÷ 2 = 2
  2. y: (4 + (−9)) ÷ 2 = −2.5
10.Find the midpoint of the segment joining (−5, −4) and (9, −4).

Answer: (2, −4)

  1. x: (−5 + 9) ÷ 2 = 2
  2. y: (−4 + (−4)) ÷ 2 = −4
11.Find the midpoint of the segment joining (5, −3) and (−3, 3).

Answer: (1, 0)

  1. x: (5 + (−3)) ÷ 2 = 1
  2. y: (−3 + 3) ÷ 2 = 0
12.Find the distance between (−5, 5) and (3, −10).

Answer: 17

  1. Horizontal change = 8, vertical change = 15
  2. d = √(82 + 152) = √289
  3. = 17
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