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8th Grade Circumference and Area of Circles Worksheet — Level 3 — Answers

Answer sheet with worked solutions for the 8th Grade area & perimeter worksheet.

Success TutoringWorksheetsAnswer sheet8th Grade · Mathematics · Area & Perimeter

8th Grade Circumference and Area of Circles Worksheet — Level 3 — Answers

Show your work. Use the π button on your calculator and round to 1 decimal place unless told otherwise.

1.A circle has a circumference of 28π cm. Find its radius and its area (leave the area in terms of π).

Answer: r = 14 cm; A = 196π cm2

  1. C = 2πr, so 2πr = 28π
  2. r = 14 cm
  3. A = πr2 = 196π cm2
2.A circle has a circumference of 24π cm. Find its radius and its area (leave the area in terms of π).

Answer: r = 12 cm; A = 144π cm2

  1. C = 2πr, so 2πr = 24π
  2. r = 12 cm
  3. A = πr2 = 144π cm2
3.Find the area of a semicircle with a radius of 20 cm, correct to 1 decimal place.

Answer: 628.3 cm2

  1. A = ½ × π × r2 = ½ × π × 400
  2. ≈ 628.3 cm2
4.A circle has a radius of 5 cm. Find its area, correct to 1 decimal place.

Answer: 78.5 cm2

  1. A = π × r2 = π × 52 = π × 25
  2. ≈ 78.5 cm2
5.A circle has a radius of 11 cm. Find its area, correct to 1 decimal place.

Answer: 380.1 cm2

  1. A = π × r2 = π × 112 = π × 121
  2. ≈ 380.1 cm2
6.A circle has a radius of 7 cm. Find its area, correct to 1 decimal place.

Answer: 153.9 cm2

  1. A = π × r2 = π × 72 = π × 49
  2. ≈ 153.9 cm2
7.A circle has a diameter of 40 cm. Find its area, correct to 1 decimal place.

Answer: 1256.6 cm2

  1. r = 40 ÷ 2 = 20 cm
  2. A = π × r2 = π × 202 = π × 400
  3. ≈ 1256.6 cm2
8.Find the area of a semicircle with a radius of 16 cm, correct to 1 decimal place.

Answer: 402.1 cm2

  1. A = ½ × π × r2 = ½ × π × 256
  2. ≈ 402.1 cm2
9.A circle has a circumference of 10π cm. Find its radius and its area (leave the area in terms of π).

Answer: r = 5 cm; A = 25π cm2

  1. C = 2πr, so 2πr = 10π
  2. r = 5 cm
  3. A = πr2 = 25π cm2
10.A circle has a radius of 10 cm. Find its area, correct to 1 decimal place.

Answer: 314.2 cm2

  1. A = π × r2 = π × 102 = π × 100
  2. ≈ 314.2 cm2
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