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8th Grade Circumference and Area of Circles Worksheet — Level 3 — Practice Set 4 — Answers

Answer sheet with worked solutions for the 8th Grade area & perimeter worksheet.

Success TutoringWorksheetsAnswer sheet8th Grade · Mathematics · Area & Perimeter

8th Grade Circumference and Area of Circles Worksheet — Level 3 — Practice Set 4 — Answers

Show your work. Use the π button on your calculator and round to 1 decimal place unless told otherwise.

1.Find the area of a semicircle with a radius of 15 cm, correct to 1 decimal place.

Answer: 353.4 cm2

  1. A = ½ × π × r2 = ½ × π × 225
  2. ≈ 353.4 cm2
2.A circle has a diameter of 40 cm. Find its area, correct to 1 decimal place.

Answer: 1256.6 cm2

  1. r = 40 ÷ 2 = 20 cm
  2. A = π × r2 = π × 202 = π × 400
  3. ≈ 1256.6 cm2
3.A circle has a diameter of 4 cm. Find its area, correct to 1 decimal place.

Answer: 12.6 cm2

  1. r = 4 ÷ 2 = 2 cm
  2. A = π × r2 = π × 22 = π × 4
  3. ≈ 12.6 cm2
4.Find the area of a semicircle with a radius of 9 cm, correct to 1 decimal place.

Answer: 127.2 cm2

  1. A = ½ × π × r2 = ½ × π × 81
  2. ≈ 127.2 cm2
5.Find the area of a semicircle with a radius of 7 cm, correct to 1 decimal place.

Answer: 77.0 cm2

  1. A = ½ × π × r2 = ½ × π × 49
  2. ≈ 77.0 cm2
6.Find the area of a semicircle with a radius of 19 cm, correct to 1 decimal place.

Answer: 567.1 cm2

  1. A = ½ × π × r2 = ½ × π × 361
  2. ≈ 567.1 cm2
7.A circle has a diameter of 6 cm. Find its area, correct to 1 decimal place.

Answer: 28.3 cm2

  1. r = 6 ÷ 2 = 3 cm
  2. A = π × r2 = π × 32 = π × 9
  3. ≈ 28.3 cm2
8.A circle has a radius of 16 cm. Find its area, correct to 1 decimal place.

Answer: 804.2 cm2

  1. A = π × r2 = π × 162 = π × 256
  2. ≈ 804.2 cm2
9.Find the area of a semicircle with a radius of 20 cm, correct to 1 decimal place.

Answer: 628.3 cm2

  1. A = ½ × π × r2 = ½ × π × 400
  2. ≈ 628.3 cm2
10.A circle has a circumference of 32π cm. Find its radius and its area (leave the area in terms of π).

Answer: r = 16 cm; A = 256π cm2

  1. C = 2πr, so 2πr = 32π
  2. r = 16 cm
  3. A = πr2 = 256π cm2
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