9th Grade Circumference and Area of Circles Worksheet — Level 3 — Practice Set 2 — Answers
Answer sheet with worked solutions for the 9th Grade area & perimeter worksheet.
Success TutoringWorksheetsAnswer sheet9th Grade · Mathematics · Area & Perimeter9th Grade Circumference and Area of Circles Worksheet — Level 3 — Practice Set 2 — Answers
Show your work. Use the π button on your calculator and round to 1 decimal place unless told otherwise.
1.Find the area of a semicircle with a radius of 13 cm, correct to 1 decimal place.
Answer: 265.5 cm2
- A = ½ × π × r2 = ½ × π × 169
- ≈ 265.5 cm2
2.A circle has a diameter of 32 cm. Find its area, correct to 1 decimal place.
Answer: 804.2 cm2
- r = 32 ÷ 2 = 16 cm
- A = π × r2 = π × 162 = π × 256
- ≈ 804.2 cm2
3.A circle has a circumference of 40π cm. Find its radius and its area (leave the area in terms of π).
Answer: r = 20 cm; A = 400π cm2
- C = 2πr, so 2πr = 40π
- r = 20 cm
- A = πr2 = 400π cm2
4.Find the area of a semicircle with a radius of 20 cm, correct to 1 decimal place.
Answer: 628.3 cm2
- A = ½ × π × r2 = ½ × π × 400
- ≈ 628.3 cm2
5.A circle has a diameter of 26 cm. Find its area, correct to 1 decimal place.
Answer: 530.9 cm2
- r = 26 ÷ 2 = 13 cm
- A = π × r2 = π × 132 = π × 169
- ≈ 530.9 cm2
6.A circle has a diameter of 36 cm. Find its area, correct to 1 decimal place.
Answer: 1017.9 cm2
- r = 36 ÷ 2 = 18 cm
- A = π × r2 = π × 182 = π × 324
- ≈ 1017.9 cm2
7.A circle has a circumference of 20π cm. Find its radius and its area (leave the area in terms of π).
Answer: r = 10 cm; A = 100π cm2
- C = 2πr, so 2πr = 20π
- r = 10 cm
- A = πr2 = 100π cm2
8.Find the area of a semicircle with a radius of 7 cm, correct to 1 decimal place.
Answer: 77.0 cm2
- A = ½ × π × r2 = ½ × π × 49
- ≈ 77.0 cm2
9.Find the area of a semicircle with a radius of 5 cm, correct to 1 decimal place.
Answer: 39.3 cm2
- A = ½ × π × r2 = ½ × π × 25
- ≈ 39.3 cm2
10.A circle has a circumference of 14π cm. Find its radius and its area (leave the area in terms of π).
Answer: r = 7 cm; A = 49π cm2
- C = 2πr, so 2πr = 14π
- r = 7 cm
- A = πr2 = 49π cm2
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