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9th Grade Trigonometry (Finding Sides) Worksheet — Level 3 — Practice Set 4 — Answers

Answer sheet with worked solutions for the 9th Grade trigonometry worksheet.

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Success TutoringWorksheetsAnswer sheet9th Grade · Mathematics · Trigonometry

9th Grade Trigonometry (Finding Sides) Worksheet — Level 3 — Practice Set 4 — Answers

Label the sides (opposite, adjacent, hypotenuse), choose the ratio (SOH CAH TOA), then solve.

1.In a right triangle, the side adjacent to a 57° angle is 9 m. Find the opposite side, to 1 decimal place.

Answer: 13.9 m

  1. tan 57° = opposite ÷ adjacent
  2. opposite = 9 × tan 57°
  3. ≈ 13.9
2.In a right triangle, the hypotenuse is 15 cm and one angle is 55°. Find the side adjacent to the 55° angle, to 1 decimal place.

Answer: 8.6 cm

  1. cos 55° = adjacent ÷ hypotenuse
  2. adjacent = 15 × cos 55°
  3. ≈ 8.6
3.In a right triangle, the side adjacent to a 50° angle is 5 m. Find the opposite side, to 1 decimal place.

Answer: 6 m

  1. tan 50° = opposite ÷ adjacent
  2. opposite = 5 × tan 50°
  3. ≈ 6
4.In a right triangle, the side adjacent to a 24° angle is 25 m. Find the opposite side, to 1 decimal place.

Answer: 11.1 m

  1. tan 24° = opposite ÷ adjacent
  2. opposite = 25 × tan 24°
  3. ≈ 11.1
5.In a right triangle, the side adjacent to a 54° angle is 8 m. Find the opposite side, to 1 decimal place.

Answer: 11 m

  1. tan 54° = opposite ÷ adjacent
  2. opposite = 8 × tan 54°
  3. ≈ 11
6.In a right triangle, the hypotenuse is 5 cm and one angle is 50°. Find the side adjacent to the 50° angle, to 1 decimal place.

Answer: 3.2 cm

  1. cos 50° = adjacent ÷ hypotenuse
  2. adjacent = 5 × cos 50°
  3. ≈ 3.2
7.In a right triangle, the hypotenuse is 18 cm and one angle is 65°. Find the side opposite the 65° angle, to 1 decimal place.

Answer: 16.3 cm

  1. sin 65° = opposite ÷ hypotenuse
  2. opposite = 18 × sin 65°
  3. ≈ 16.3
8.In a right triangle, the hypotenuse is 26 cm and one angle is 52°. Find the side adjacent to the 52° angle, to 1 decimal place.

Answer: 16 cm

  1. cos 52° = adjacent ÷ hypotenuse
  2. adjacent = 26 × cos 52°
  3. ≈ 16
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