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Year 10 Gradient and Linear Equations Worksheet — Level 2 — Practice Set 2 — Answers

Answer sheet with worked solutions for the Year 10 linear relationships & graphs worksheet.

Success TutoringWorksheetsAnswer sheetYear 10 · Mathematics · Linear Relationships & Graphs

Year 10 Gradient and Linear Equations Worksheet — Level 2 — Practice Set 2 — Answers

Show your working. Gradient = rise ÷ run; the equation of a line can be written as y = (gradient)x + (y-intercept).

1.Find the gradient of the line through (3, −1) and (7, 4).

Answer:

  1. gradient = rise ÷ run = (4 − (−1)) ÷ (7 − 3)
  2. = 5 ÷ 4 =
2.For the line y = 2x + 6, write the gradient and the y-intercept.

Answer: gradient 2; y-intercept 6

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

3.A line has a gradient of 2 and passes through (−3, −12). Find its equation.

Answer: y = 2x − 6

  1. y = 2x + (y-intercept)
  2. −12 = 2 × (−3) + (y-intercept)
  3. y-intercept = −12 − (−6) = −6
  4. y = 2x − 6
4.A line has a gradient of 4 and passes through (2, 10). Find its equation.

Answer: y = 4x + 2

  1. y = 4x + (y-intercept)
  2. 10 = 4 × 2 + (y-intercept)
  3. y-intercept = 10 − 8 = 2
  4. y = 4x + 2
5.For the line y = −6x − 7, write the gradient and the y-intercept.

Answer: gradient −6; y-intercept −7

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

6.A line has a gradient of −1 and passes through (−2, 11). Find its equation.

Answer: y = −x + 9

  1. y = −1x + (y-intercept)
  2. 11 = −1 × (−2) + (y-intercept)
  3. y-intercept = 11 − 2 = 9
  4. y = −x + 9
7.Find the gradient of the line through (5, −3) and (7, −7).

Answer: −2

  1. gradient = rise ÷ run = (−7 − (−3)) ÷ (7 − 5)
  2. = −4 ÷ 2 = −2
8.For the line y = 4x + 6, write the gradient and the y-intercept.

Answer: gradient 4; y-intercept 6

In y = (gradient)x + (y-intercept), the number multiplying x is the gradient and the constant is where the line crosses the y-axis.

9.Find the gradient of the line through (1, 2) and (6, 9).

Answer:

  1. gradient = rise ÷ run = (9 − 2) ÷ (6 − 1)
  2. = 7 ÷ 5 =
10.A line has a gradient of −3 and passes through (0, 3). Find its equation.

Answer: y = −3x + 3

  1. y = −3x + (y-intercept)
  2. 3 = −3 × 0 + (y-intercept)
  3. y-intercept = 3 − 0 = 3
  4. y = −3x + 3
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