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11th Grade Systems of Equations Worksheet — Level 3 — Answers

Answer sheet with worked solutions for the 11th Grade systems of equations worksheet.

Success TutoringWorksheetsAnswer sheet11th Grade · Mathematics · Simultaneous Equations

11th Grade Systems of Equations Worksheet — Level 3 — Answers

Solve each pair of equations. Check your solution satisfies both equations.

1.Solve the system: 2x + 2y = 10 and 3x + 2y = 17

Answer: x = 7, y = −2

  1. Multiply equation 1 by 3 and equation 2 by 2 to match the x coefficients
  2. 6x + 6y = 30 and 6x + 4y = 34
  3. Subtract: 2y = −4, so y = −2
  4. Substitute back: x = 7
2.Solve the system: 3x − 2y = −32 and 2x − 5y = −47

Answer: x = −6, y = 7

  1. Multiply equation 1 by 2 and equation 2 by 3 to match the x coefficients
  2. 6x − 4y = −64 and 6x − 15y = −141
  3. Subtract: 11y = 77, so y = 7
  4. Substitute back: x = −6
3.Solve the system: 4x − 3y = −17 and 3x + 2y = −17

Answer: x = −5, y = −1

  1. Multiply equation 1 by 3 and equation 2 by 4 to match the x coefficients
  2. 12x − 9y = −51 and 12x + 8y = −68
  3. Subtract: −17y = 17, so y = −1
  4. Substitute back: x = −5
4.Solve the system: 2x − 3y = 30 and 5x + 3y = 12

Answer: x = 6, y = −6

  1. Multiply equation 1 by 5 and equation 2 by 2 to match the x coefficients
  2. 10x − 15y = 150 and 10x + 6y = 24
  3. Subtract: −21y = 126, so y = −6
  4. Substitute back: x = 6
5.Solve the system: 2x − 2y = −4 and 4x + y = −28

Answer: x = −6, y = −4

  1. Multiply equation 1 by 4 and equation 2 by 2 to match the x coefficients
  2. 8x − 8y = −16 and 8x + 2y = −56
  3. Subtract: −10y = 40, so y = −4
  4. Substitute back: x = −6
6.Solve the system: 3x + 2y = −11 and 4x + 4y = −12

Answer: x = −5, y = 2

  1. Multiply equation 1 by 4 and equation 2 by 3 to match the x coefficients
  2. 12x + 8y = −44 and 12x + 12y = −36
  3. Subtract: −4y = −8, so y = 2
  4. Substitute back: x = −5
7.Solve the system: 3x − 3y = −15 and 5x + y = −1

Answer: x = −1, y = 4

  1. Multiply equation 1 by 5 and equation 2 by 3 to match the x coefficients
  2. 15x − 15y = −75 and 15x + 3y = −3
  3. Subtract: −18y = −72, so y = 4
  4. Substitute back: x = −1
8.Solve the system: 3x + 4y = −10 and 3x − 4y = −2

Answer: x = −2, y = −1

  1. Subtract equation 2 from equation 1: 8y = −8
  2. y = −1
  3. Substitute into equation 1: 3x − 4 = −10, so x = −2
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