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11th Grade Systems of Equations Worksheet — Level 3 — Practice Set 2 — Answers

Answer sheet with worked solutions for the 11th Grade systems of equations worksheet.

Success TutoringWorksheetsAnswer sheet11th Grade · Mathematics · Simultaneous Equations

11th Grade Systems of Equations Worksheet — Level 3 — Practice Set 2 — Answers

Solve each pair of equations. Check your solution satisfies both equations.

1.Solve the system: 2x − 2y = −24 and 3x + 2y = 4

Answer: x = −4, y = 8

  1. Multiply equation 1 by 3 and equation 2 by 2 to match the x coefficients
  2. 6x − 6y = −72 and 6x + 4y = 8
  3. Subtract: −10y = −80, so y = 8
  4. Substitute back: x = −4
2.Solve the system: 3x − 4y = 3 and 5x − 4y = −3

Answer: x = −3, y = −3

  1. Multiply equation 1 by 5 and equation 2 by 3 to match the x coefficients
  2. 15x − 20y = 15 and 15x − 12y = −9
  3. Subtract: −8y = 24, so y = −3
  4. Substitute back: x = −3
3.Solve the system: 4x + 3y = −2 and 4x − y = 6

Answer: x = 1, y = −2

  1. Subtract equation 2 from equation 1: 4y = −8
  2. y = −2
  3. Substitute into equation 1: 4x − 6 = −2, so x = 1
4.Solve the system: 2x − 2y = 24 and 5x + y = 24

Answer: x = 6, y = −6

  1. Multiply equation 1 by 5 and equation 2 by 2 to match the x coefficients
  2. 10x − 10y = 120 and 10x + 2y = 48
  3. Subtract: −12y = 72, so y = −6
  4. Substitute back: x = 6
5.Solve the system: 3x − y = 0 and 4x + 5y = 38

Answer: x = 2, y = 6

  1. Multiply equation 1 by 4 and equation 2 by 3 to match the x coefficients
  2. 12x − 4y = 0 and 12x + 15y = 114
  3. Subtract: −19y = −114, so y = 6
  4. Substitute back: x = 2
6.Solve the system: 2x − y = 13 and 4x + 3y = 21

Answer: x = 6, y = −1

  1. Multiply equation 1 by 4 and equation 2 by 2 to match the x coefficients
  2. 8x − 4y = 52 and 8x + 6y = 42
  3. Subtract: −10y = 10, so y = −1
  4. Substitute back: x = 6
7.Solve the system: 3x − y = −16 and 2x − 2y = −16

Answer: x = −4, y = 4

  1. Multiply equation 1 by 2 and equation 2 by 3 to match the x coefficients
  2. 6x − 2y = −32 and 6x − 6y = −48
  3. Subtract: 4y = 16, so y = 4
  4. Substitute back: x = −4
8.Solve the system: 4x − 2y = −30 and 4x + 5y = 19

Answer: x = −4, y = 7

  1. Subtract equation 2 from equation 1: −7y = −49
  2. y = 7
  3. Substitute into equation 1: 4x − 14 = −30, so x = −4
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