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Study Guide12th GradeLevel 3 · Challenge

Free 12th Grade Integration Basics

Introduces integration as the reverse of differentiation, sets out the power rule for integrating, explains the constant of integration, and shows how to evaluate definite integrals to find the area under a curve. Worked examples cover polynomials, negative powers, finding a function from its derivative and area problems.

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Grade
12th Grade
Subject
Math
Topic
Calculus
Difficulty
Level 3 · Challenge
Estimated time
20 minutes
Curriculum
Texas grade levels (TEKS)
Answers
Not applicable
Format
PDF (A4) + print

Students will practice

  • understanding integration as anti-differentiation
  • applying the power rule for integration
  • including and finding the constant of integration
  • evaluating definite integrals and finding areas under curves

Curriculum: Texas grade levels (TEKS). We show specific outcome codes only where they have been verified against the official curriculum document.

What's next?

Completed: Integration Basics

  1. 1Differentiating Exponential, Logarithmic and Trigonometric Functions
  2. 2Motion in a Straight Line: Displacement, Velocity and Acceleration
  3. 3Senior Calculus Practice with Worked Solutions
  4. 412th Grade Differentiation (Power Rule) Worksheet — Level 1

How to use this study guide

  1. Read it together first, pausing at each worked example to try the step before reading the answer.
  2. Attempt the "Check yourself" questions at the end without looking back.
  3. Then practice with a worksheet from the pathway above and finish with the topic test.

Common questions

Who is this study guide for?

12th Grade students (typically ages 17–18) working on calculus. It is pitched at level 3 · challenge.

Are the answers included?

This is a study guide, so there is no separate answer sheet; the 'Check yourself' questions include answers.

How long does it take?

About 20 minutes. Short, regular sessions work best: two or three a week beats one long one.

Do I need to sign up to download?

No. Click Download Free PDF and it opens immediately. It is free for personal, classroom and homeschool use.

What should we do next?

Try Differentiating Exponential, Logarithmic and Trigonometric Functions.

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Success TutoringWorksheets12th Grade · Mathematics · Calculus

Integration Basics

What you need to know

Integration is the reverse of differentiation. Differentiating x3 gives 3x2, so integrating 3x2 gives back x3 — almost. Because the derivative of any constant is 0, integrating 3x2 could give x3 + 1 or x3 − 7 just as well. We write the answer as x3 + C, where C is the constant of integration. The integral sign is ∫, and ∫ f(x) dx means "integrate f(x) with respect to x".

The power rule for integration. ∫ x[sup n] dx = [frac x[sup n + 1]/n + 1] + C (for n ≠ −1). Raise the power by 1, then divide by the new power. Constant multipliers stay in front, and sums are integrated term by term.

IntegrandIntegralCheck by differentiating
x2 + C3 × = x2
x + C2 × = x
5 (a constant)5x + Cderivative of 5x is 5
6x5x6 + C6x5
x−2 + C = − + C−(−1)x−2 = x−2

∫ (4x3 − 6x + 2) dx

  1. 4x3 → 4 × = x4
  2. −6x → −6 × = −3x2
  3. 2 → 2x
  4. Answer: x[sup 4] − 3x[sup 2] + 2x + C
  5. Check by differentiating: 4x3 − 6x + 2. Correct.

Rewrite first: ∫ dx

  1. Write as a power: 3x−2
  2. Integrate: 3 × = −3x−1
  3. Answer: −[frac 3/x] + C
Common mistake: leaving out + C in an indefinite integral, or dividing by the old power instead of the new one. ∫ x2 dx is , not . Always differentiate your answer in your head to check.

f′(x) = 2x + 3 and f(1) = 6. Find f(x).

  1. Integrate: f(x) = x2 + 3x + C
  2. Use the given point: f(1) = 1 + 3 + C = 6, so C = 2
  3. f(x) = x[sup 2] + 3x + 2

Definite integrals and area. A definite integral has limits: ∫ from a to b of f(x) dx. Integrate, then substitute the upper limit and subtract the value at the lower limit: F(b) − F(a). The constant C cancels, so it is left out. When f(x) ≥ 0 between a and b, the definite integral gives the area between the curve and the x-axis.

Two definite integrals

  1. Area under y = x2 from x = 0 to x = 3: F(x) = .
  2. F(3) = = 9 and F(0) = 0, so the area is 9 − 0 = 9 square units.
  3. ∫ from 1 to 2 of (3x2 + 1) dx: F(x) = x3 + x.
  4. F(2) = 8 + 2 = 10 and F(1) = 1 + 1 = 2, so the answer is 10 − 2 = 8.
If the curve dips below the x-axis, the definite integral of that part is negative. To find a total area, split the integral at the x-intercepts and add the absolute values of each piece.

Check yourself

  1. ∫ x4 dx
  2. ∫ (6x2 − 4x + 5) dx
  3. ∫ dx
  4. f′(x) = 4x and f(2) = 10. Find f(x).
  5. ∫ from 0 to 2 of x3 dx
  6. Find the area under y = 2x + 1 from x = 1 to x = 3.

Answers: 1. + C 2. 2x3 − 2x2 + 5x + C 3. − + C (that is, + C) 4. f(x) = 2x2 + C with 8 + C = 10, so f(x) = 2x2 + 2 5. − 0 = 4 6. F(x) = x2 + x; F(3) − F(1) = 12 − 2 = 10 square units

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Calculus in other year levels

About this resource

Created by
Success Tutoring
Last reviewed
1 October 2026
How it was made
Written by our team

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